(0)=-4.9t^2+5.4t+10

Solution for (0)=-4.9t^2+5.4t+10 equation:

(0)=-4.9t^2+5.4t+10

We move all terms to the left:

(0)-(-4.9t^2+5.4t+10)=0

We add all the numbers together, and all the variables

-(-4.9t^2+5.4t+10)=0

We get rid of parentheses

4.9t^2-5.4t-10=0

a = 4.9; b = -5.4; c = -10;
Δ = b2-4ac
Δ = -5.42-4·4.9·(-10)
Δ = 225.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.4)-\sqrt{225.16}}{2*4.9}=\frac{5.4-\sqrt{225.16}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.4)+\sqrt{225.16}}{2*4.9}=\frac{5.4+\sqrt{225.16}}{9.8}
$